Solve- 1 - sin -2 - y

1 sin(π2 y) =1 cos y =1 cos^2(y2)+sin^2y2 =2sin^2y2 ∴ 1 sin(π2 y)=2sin^2(y2) ...

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Domain and Range of Basic Inverse Trigonometric Functions

Solve: 1 - ...

Question

Solve: $1 - sin (\frac{π}{2} - y)$

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Solution

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sin x + sin (\frac{π}{2} \sqrt{(1 - cos 2 x)^{2} + {sin}^{2} 2 x}) = 0, x \in [\frac{5 π}{2}, \frac{7 π}{2}]

sin (\frac{π}{2} - {sin}^{- 1} (\frac{1}{2}))

f (x) = \int s i n \frac{π}{2} (x + 1), x \leq 0

sin \frac{π}{18} sin \frac{3 π}{18} sin \frac{5 π}{18} sin \frac{7 π}{18} = \frac{1}{16}

t a n x + s i n (π + x) = 2 s i n^{2} \frac{x}{2} .

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