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Question

Solve (1tan2θ)(1+tan2θ)+2tan2θ=0 in the interval (π/2,π/2).

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Solution

Let us put tan2θ=t
(1t)(1+t)+2t=0
or 1t2+2t=0
It is clearly satisfied by t=3
as 8+8=0
tan2θ=3 or tanθ=±3
θ=±π/3 in the given interval.

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