Question

Solve:

$10\le -5(x-2)<20$

Answer 1

We have,

$10\le -5(x-2)<20$

$2\le -(x-2)<4$

$-2\ge (x-2)>-4$

$-2+2\ge x>-4+2$

$0\ge x>-2$

Hence, this is the answer.