Solve $(12 + 2 \frac{1}{3}) - \frac{1}{3}$ .

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Solution

We know that $(x + y) - z = x + (y - z)$ , for all numbers $x$ , $y$ , $z$ with $y > z$ .

Since the above is true for all the numbers, it must be true for $x = 12$ , $y = 2 \frac{1}{3}$ and $z = \frac{1}{3}$ also, as $y = 2 \frac{1}{3} > \frac{1}{3} = z$

So, $(12 + 2 \frac{1}{3}) - \frac{1}{3}$ = $12 + (2 \frac{1}{3} - \frac{1}{3})$ = $12 + (\frac{7}{3} - \frac{1}{3})$ = $12 + 2$ = $14$

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