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Question

Solve: 12[5y+2x(y22x+2)+6y(y21)]×2.

A
8x2+y24xy28x22y+10
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B
8x2+2y2+4xy28x22y+10
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C
8x2+2y24xy28x22y+10
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D
8x2+2y24xy28x+22y+10
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Solution

The correct option is C 8x2+2y24xy28x22y+10
12[5y+2x(y22x+2)+6y(y21)]×0.1
We need to follow BODMAS rule.
=> Brackets (parts of a calculation inside brackets always come first).
=> Orders (numbers involving powers or square roots).
=> Division.
=> Multiplication.
=> Addition.
=> Subtraction.
= 12[5y+2xy24x2+4x+6yy2+1]×2
= 12[2xy24x2+4x+11yy2+1]×2
= 12[4xy28x2+8x+22y2y2+2]
= 124xy2+8x28x22y+2y22
= 8x2+2y24xy28x22y+10

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