The correct option is C 8x2+2y2−4xy2−8x−22y+10
12−[5y+2x(y2−2x+2)+6y−(y2−1)]×0.1
We need to follow BODMAS rule.
=> Brackets (parts of a calculation inside brackets always come first).
=> Orders (numbers involving powers or square roots).
=> Division.
=> Multiplication.
=> Addition.
=> Subtraction.
= 12−[5y+2xy2−4x2+4x+6y−y2+1]×2
= 12−[2xy2−4x2+4x+11y−y2+1]×2
= 12−[4xy2−8x2+8x+22y−2y2+2]
= 12−4xy2+8x2−8x−22y+2y2−2
= 8x2+2y2−4xy2−8x−22y+10