Solve- 12-5y-2xy2-2x-2-6y-y2-1- 2-

The correct option is C 8x^2+2y^2 4xy^2 8x 22y+10 12 [5y+2x(y^2 2x+2)+6y (y^2 1)]× 0.1 We need to follow BODMAS rule.= gt; Brackets (parts of a cal ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Simplification of an Expression

Solve: 12-[...

Question

Solve: $12 - [5 y + 2 x (y^{2} - 2 x + 2) + 6 y - (y^{2} - 1)] \times 2$ .

8 x^{2} + y^{2} - 4 x y^{2} - 8 x - 22 y + 10

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 x^{2} + 2 y^{2} + 4 x y^{2} - 8 x - 22 y + 10

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 x^{2} + 2 y^{2} - 4 x y^{2} - 8 x - 22 y + 10

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

8 x^{2} + 2 y^{2} - 4 x y^{2} - 8 x + 22 y + 10

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $8 x^{2} + 2 y^{2} - 4 x y^{2} - 8 x - 22 y + 10$
$12 - [5 y + 2 x (y^{2} - 2 x + 2) + 6 y - (y^{2} - 1)] \times 0.1$
We need to follow BODMAS rule.
=> Brackets (parts of a calculation inside brackets always come first).
=> Orders (numbers involving powers or square roots).
=> Division.
=> Multiplication.
=> Addition.
=> Subtraction.
$=$ $12 - [5 y + 2 x y^{2} - 4 x^{2} + 4 x + 6 y - y^{2} + 1] \times 2$
$=$ $12 - [2 x y^{2} - 4 x^{2} + 4 x + 11 y - y^{2} + 1] \times 2$
$=$ $12 - [4 x y^{2} - 8 x^{2} + 8 x + 22 y - 2 y^{2} + 2]$
$=$ $12 - 4 x y^{2} + 8 x^{2} - 8 x - 22 y + 2 y^{2} - 2$
$=$ $8 x^{2} + 2 y^{2} - 4 x y^{2} - 8 x - 22 y + 10$

Suggest Corrections

Similar questions

(x^{2} + y^{2}) \frac{d y}{d x} = 8 x^{2} - 3 x y + 2 y^{2}

Q. Factorize the following:

8 x^{2} - 14 x + 8 x - 14

Q. The equation(s) of the circle passing through the points of intersection of the circles

x^{2} + y^{2} - 2 x - 4 y - 4 = 0,

x^{2} + y^{2} - 10 x - 12 y + 40 = 0

and having radius

4

units is/are

Q. Solve the following inequalities.

x^{2} 2^{2 x} + 9 (x + 2) 2^{x} + 8 x^{2} ⩽ (x + 2) 2^{2 x} + 9 x^{2} 2^{x} + 8 x + 16

Q. Solve

5 y - 2 (2 y - 7) = 2 (3 y - 1) + \frac{7}{2}

Join BYJU'S Learning Program

Solve: 12−[5y+2x(y2−2x+2)+6y−(y2−1)]×2.

Solve: $12 - [5 y + 2 x (y^{2} - 2 x + 2) + 6 y - (y^{2} - 1)] \times 2$ .