12x^2 27=0 ⇒ 3(4x^2 9)=0 ⇒ 3(2x+3)(2x 3)=0 ⇒ (2x+3)(2x 3)=0/3 ⇒ (2x+3)(2x 3)=0 ⇒ 2x+3=0 #160; #160; #1 ...

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Expansion of (x^2 - y^2)

Solve: 12x2...

Question

Solve: $12 x^{2} - 27 = 0$

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Solution

$12 x^{2} - 27 = 0$

$\Rightarrow$ $3 (4 x^{2} - 9) = 0$

$\Rightarrow$ $3 (2 x + 3) (2 x - 3) = 0$

$\Rightarrow$ $(2 x + 3) (2 x - 3) = 0 / 3$

$\Rightarrow (2 x + 3) (2 x - 3) = 0$

$\Rightarrow$ $2 x + 3 = 0$ $2 x - 3 = 0$

$\Rightarrow$ $2 x = - 3$ $2 x = 3$

$\Rightarrow$ $x = - \frac{3}{2}$ $x = \frac{3}{2}$

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