Question

Solve:
$\frac{15(2-y)-5(y+6)}{1-3y}=10$

Answer 1

$\frac{15(2-y)-5(y+6)}{1-3y}=10$

$\Rightarrow \frac{30-15y-5y-30}{1-3y}=10$

$\Rightarrow \frac{-20y}{1-3y}=10$

$\Rightarrow (-20y)=10(1-3y)$ (by cross multiplication)

$\Rightarrow -20y=10-30y$

$\Rightarrow -20y+30y=10$

$\Rightarrow 10y=10$

$\Rightarrow y=\frac{10}{10}=1$

$\therefore y=1$