The correct option is B x=8,y=12,z=20
We have,
15x=10y=6z............(1)
7x+9y+9z=344.............(2)
From equation (1) we have,
15x=10y
⇒y=32x............(3)
Also, 15x=6z
⇒z=52x..........(4)
Substituting equation (3) and equation (4) in the equation (2), we get
7x+9(32x)+9(52x)=344
⇒14x+27x+45x2=344
⇒86x2=344
⇒x=8..........(5)
Substituting equation (5) in equation (3), we get
y=32(8)
⇒y=12
Substituting equation (5) in equation (4), we get
z=52(8)
⇒z=20
Thus, we have x=8,y=12,z=20