Question

Solve: $16(3x-5)-10(4x-8)=40$

Answer 1

Finding the solution of algebraic equation

The given equation is $16(3x-5)-10(4x-8)=40$

$$\begin{gathered} \Rightarrow 48x-80-40x+80=40 \\ \Rightarrow 8x+0=40 \\ \Rightarrow 8x=40 \\ \Rightarrow x=\frac{40}{8} \\ \Rightarrow x=5 \end{gathered}$$

Hence, $x=5$ is the solution of given equation.