We have, #10; #10; 16a^2 b^2+4a+b #10; #10; =( 4a )^2 b^2+( 4a+b ) #10; #10; =( 4a+b )( 4a b )+( 4a+b #10;) #10; #10; =( 4a ...

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Factorisation by Common Factors

Solve: 16a2...

Question

Solve: $16 a^{2} - b^{2} + 4 a + b$

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Solution

We have,

$16 a^{2} - b^{2} + 4 a + b$

$= {(4 a)}^{2} - b^{2} + (4 a + b)$

$= (4 a + b) (4 a - b) + (4 a + b)$

$= (4 a + b) (4 a - b + 1)$

Hence, this is the answer.

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