MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Factorisation by Regrouping Terms

Solve : 16x ...

Question

Solve :
${16 x}^{2} - y^{2} + 14 y - 49$

Open in App

Solution

$= 16 x^{2} - (y^{2} - 14 y + 49)$
$= {(4 x)}^{2} - (y^{2} - 2 \times 7 \times y + 49)$
$= {(4 x)}^{2} - {(y - 7)}^{2}$
$= (4 x + y - 7) (4 x - y + 7)$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The equation of the circle touching the

y -

axis whose radius is

5

y -

coordinate of the centre is

- 7,

Q. The equation of a circle whose radius is

7

x -

coordinate of the centre is

- 2

and also touches the

x -

Q. Question 90 (iii)

Factorise the following, using the identity,

a^{2} - 2 a b + b^{2} = (a - b)^{2}

y^{2} - 14 y + 49

Q. Find the foci of the curve

16 x^{2} - 24 x y + 9 y^{2} + 28 x + 14 y + 21 = 0

(16 x^{3} y^{2} z^{2} + 16 x^{2} y^{2} z^{3} + 16 x^{2} y^{3} z^{2}) \div 8 x y z

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Method of Common Factors

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Factorisation by Regrouping Terms

Standard VIII Mathematics

Join BYJU'S Learning Program

CrossIcon