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Factorisation by Regrouping Terms

Solve : 16x ...

Question

Solve :
${16 x}^{2} - y^{2} + 14 y - 49$

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Solution

$= 16 x^{2} - (y^{2} - 14 y + 49)$
$= {(4 x)}^{2} - (y^{2} - 2 \times 7 \times y + 49)$
$= {(4 x)}^{2} - {(y - 7)}^{2}$
$= (4 x + y - 7) (4 x - y + 7)$

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Factorisation by Regrouping Terms

Standard VIII Mathematics

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