Question

Solve $-18\le 3(2x-4)<12$

• A. $[-1,\infty )$
• B. $(4,\infty )$
• C. $[-1,4)$
• D. $(-\infty ,-1]\cup (4,\infty )$

Answer 1

The correct option is C $[-1,4)$

$-18\le 3(2x-4)<12\Rightarrow -18\le 6(x-2)<12\Rightarrow -3\le x-2<2\Rightarrow -1\le x<4$
therefore, solution of inqualities $[-1,4)$