The correct option is A u = 2, v = 1
2(3u−v)=5uv⇒6v−2u=5
2(u+3v)=5uv⇒2v+6u=5
Putting 1v=x and 1u=y, we get
6x−2y=5……(1)
2x+6y=−2……(2)
Multiplying Equation (1), and Equation (2) by 3 and 1 respectively, we have
18x−6y=15 and 2x+6y=5
Adding these two equations, we get 20x=20, i.e., x=1
From Equation (1), y=(6x−52)=(6×1−52)=12
∴u=1y=2 and v=1x=1