Question

Solve:
$(2^5÷2^9)\times 2^{-7}$

Answer 1

We have,

$\left(2^5÷2^9\right)\times 2^{-7}$

$=\frac{2^5}{2^9}\times 2^{-7}$

$=\frac{2^5}{2^9}\times \frac{1}{2^7}$

$=\frac{2^5}{2^{9+7}}$

$=\frac{2^5}{2^{16}}$

$=\frac{2^5}{2^5\times 2^{11}}$

$=\frac{1}{2^{11}}$

$=\frac{1}{2048}$

Thus,

We get $=\frac{1}{2048}$