Solve - 2 cos 2212o sin 22 12o

2cos2212^∘sin2212^∘=? Apply the formula 2sin Acos A=sin 2A 2cos2212^∘sin2212^∘ =sin (2× 2212 #160; )^∘ =sin 45^∘ =1√(2) ...

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Standard XII

Mathematics

Particular Solution of a Differential Equation

Solve : 2 c...

Question

Solve : $2 cos 22 {\frac{1}{2}}^{o} sin 22 {\frac{1}{2}}^{o}$

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Solution

$2 cos 22 {\frac{1}{2}}^{\circ} sin 22 {\frac{1}{2}}^{\circ} = ?$

Apply the formula $2 sin A cos A = sin 2 A$

$2 cos 22 {\frac{1}{2}}^{\circ} sin 22 {\frac{1}{2}}^{\circ}$

$= sin {(2 \times 22 \frac{1}{2})}^{\circ}$

$= sin 45^{\circ}$

$= \frac{1}{\sqrt{2}}$

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Solve : 2cos2212osin2212o

2cos2212∘sin2212∘=?Apply the formula 2sinAcosA=sin2A2cos2212∘sin2212∘=sin(2×2212)∘=sin45∘=1√2

Solve : $2 cos 22 {\frac{1}{2}}^{o} sin 22 {\frac{1}{2}}^{o}$

$2 cos 22 {\frac{1}{2}}^{\circ} sin 22 {\frac{1}{2}}^{\circ} = ?$

Apply the formula $2 sin A cos A = sin 2 A$

$2 cos 22 {\frac{1}{2}}^{\circ} sin 22 {\frac{1}{2}}^{\circ}$

$= sin {(2 \times 22 \frac{1}{2})}^{\circ}$

$= sin 45^{\circ}$

$= \frac{1}{\sqrt{2}}$