MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Solving Equations with Variable on Both Sides

Solve 2+ 2x...

Question

Solve $2 + \frac{2 x - 3}{2 x + 3} = \frac{3 x + 4}{x + 2}$

A

\frac{2}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

\frac{- 2}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

\frac{3}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

- 3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $- 3$
$2 + \frac{2 x - 3}{2 x + 3} = \frac{3 x + 4}{x + 2}$
multiply above equation by $(2 x + 3) (x + 2)$
$\Rightarrow 2 (2 x + 3) (x + 2) + (2 x - 3) (x + 2) = (3 x + 4) (2 x + 3)$
$\Rightarrow (4 x^{2} + 14 x + 12) + (2 x^{2} + x - 6) = (6 x^{2} + 17 x + 12)$
$\Rightarrow 15 x - 17 x 12 - 6$
$\Rightarrow - 2 x = 6$
$\Rightarrow x = - \frac{6}{2}$
$∴ x = - 3$

Suggest Corrections

thumbs-up

1

Similar questions

\frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x

Q. Solve the equations:

\frac{3 x^{4} + x^{2} - 2 x - 3}{3 x^{4} - x^{2} + 2 x + 3} = \frac{5 x^{4} + 2 x^{2} - 7 x + 3}{5 x^{4} - 2 x^{2} + 7 x - 3}

Q. Solve for x :

2 + \frac{2 x - 3}{2 x + 3} = \frac{3 x + 4}{x + 2}

lim x \to - 2 \frac{x^{4} + 2 x^{3} + 3 x^{2} + 5 x - 2}{x^{5} + 3 x^{4} + 2 x^{3} + 3 x^{2} + 7 x + 2}

Q. Solve the equations:

\frac{2 x^{3} - 3 x^{2} + x + 1}{2 x^{3} - 3 x^{2} - x - 1} = \frac{3 x^{3} - x^{2} + 5 x - 13}{3 x^{3} - x^{2} - 5 x + 13}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Solving an Equation with the Variable on Both Sides

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Solving Equations with Variable on Both Sides

Standard VII Mathematics

Join BYJU'S Learning Program

CrossIcon