Solve $2 log x - l o g y = 1$ where base of the logarithm is $10$ .

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Solution

$2 l o g (x) - l o g (y) = 1$

$l o g (x^{2}) - l o g (y) = l o g (10) ∵ l o g (10) = 1$

$l o g (\frac{x^{2}}{y}) = l o g (10)$

$\frac{x^{2}}{y} = 10$

$x^{2} = 10 y$

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