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Question

Solve 2sin2x3sinx+10,xϵ[0,π]

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Solution

2sin2x3sinx+10
2sin2x2sinxsinx+10
2sinx(sinx1)1(sinx1)0
(2sinx1)(sinx1)0.
In x [0,π]
Solution is [0,π6][5π6,π]{π2}

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