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Question

Solve: 2sin2x+sin22x=2

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Solution

2sin2x+sin22x=2
2sin2x+4sin2xcos2x=2
2sin2x(1+2cos2x)=2
sin2x(2cos2x+sin2x)=1
sin2x=2cos2x+sin2x=1
2cos2x=0
x=π2,3π2,5π2
x=(2n+1)π2

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