Solve 2010 - 1990 using a standard identity-

The correct option is C 39999002010 = (2000 + 10) 1990 = (2000 10) nbsp; Identity: (a nbsp;+ b)(a nbsp; b) = a^2 b^2 (2000 + 10)(2000 10) = 2000^2 ...

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Standard VII

Mathematics

(a+b)(a-b) Expansion and Visualisation

Solve 2010 × ...

Question

Solve 2010 $\times$ 1990 using a standard identity.

39999000

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2999900

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3999900

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4999900

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Solution

The correct option is C $3999900$
2010 = (2000 + 10)
1990 = (2000 -10)

Identity:
$(a + b) (a - b)$ = $a^{2}$ - $b^{2}$
$(2000 + 10) (2000 - 10)$ = $2000^{2}$ - $10^{2}$
= $4000000 - 100$
= $3999900$

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Solve 2010 × 1990 using a standard identity.

The correct option is C 39999002010 = (2000 + 10) 1990 = (2000 -10) Identity: (a+b)(a−b) = a2 - b2 (2000+10)(2000−10) = 20002-102 = 4000000−100 = 3999900

Solve 2010 $\times$ 1990 using a standard identity.

The correct option is C $3999900$
2010 = (2000 + 10)
1990 = (2000 -10)

Identity:
$(a + b) (a - b)$ = $a^{2}$ - $b^{2}$
$(2000 + 10) (2000 - 10)$ = $2000^{2}$ - $10^{2}$
= $4000000 - 100$
= $3999900$