(205)^2 (195)^2 =(205 195)(205+195) #160; #160; #160; ...... #160; #160;using A^2 B^2=(A B)(A+B) =10× 400=4000 ...

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Algebraic Identities

Solve: 2052...

Question

Solve: $(205)^{2} - (195)^{2}$

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Solution

$(205)^{2} - (195)^{2}$

$= (205 - 195) (205 + 195)$ ...... using $A^{2} - B^{2} = (A - B) (A + B)$

$= 10 \times 400 = 4000$

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