Question

Solve
$27x^3-\frac{64}{x^3}$

Answer 1

$A]27x^3-\frac{64}{x^3}=0$

= Let $x^3=y$ $=x^2=\frac{2}{3}$

$={27}_y-\frac{64}{y}=0$ $=x^2=\frac{4}{3}$

$=\frac{27y^2-64}{y}=0$ $=\pm \sqrt{\frac{4}{3}}=\pm \frac{2}{\sqrt{3}}$

$=27y^2-64=0$

$=27y^2=64$

$=y^2=64/27$

$=(x^3{)}^2=64/27$

$=(x^3{)}^2=2^3\times 2^3/3^3$

$=\left(x^{2\times 3}\right)=\frac{(2\times 2{)}^{3+3}}{3^3}$+