solve :2log base 2 (log x to the base 2)+ log base 1/2 (log 2 root 2x to the base 2)=1

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1. if a,b,c,d are in ap then log a to base x, log b to base x, log c to base x are in ?

2.the value of (1/sq root27)^2-(log16 base5/ 2log9 base5)

2 log x - l o g y = 1

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9^{1 + log x} - 3^{1 + log x} - 210 = 0,

\sqrt{log (- x)} = log \sqrt{x^{2}}

4^{{log}_{2} log x} = log x - {(log x)}^{2} + 1

x

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