Question

Solve $2n^2+n+45=0$

Answer 1

Quadratic equations are commonly solved using factorisation method.
The equation you have provided will not have any real roots.
Considering a correction in the equation as:
$2n^2+n-45=02n^2+10n-9n-45=02n(n+5)-9(n+5)=0(2n-9)(n+5)=0$
so, $n=\frac{9}{2}$ or $n=(-5)$.