Question

Solve:
$2x^2+\sqrt{6}x-6=0$

Answer 1

$2x^2-\sqrt{6x}-6=0$

$2x^2-2\sqrt{6x}+\sqrt{6x}-6=0$

$2x(x-\sqrt{6})+\sqrt{6}(x-\sqrt{6})=0$

$(2x+\sqrt{6})(x-\sqrt{6})=0$

so $x=\frac{-\sqrt{6}}{2},\sqrt{6}$.