Solve

$2 x^{2} + x + 1 = 0$

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Solution

Here $2 x^{2} + x + 1 = 0$

Comparing the given quadratic equation with

$a x^{2} + b x + c = 0$ we have

$a = 2, b = 1$ and $c = 1$

$∴ x = \frac{- 1 \pm \sqrt{(1)^{2} - 4 \times 2 \times 1}}{2 \times 2}$

$= \frac{- 1 \pm \sqrt{- 7}}{4} = \frac{- 1 \pm \sqrt{7} i}{4}$

Thus $x = \frac{- 1 + \sqrt{7} i}{4} a n d x = \frac{- 1 - \sqrt{7} i}{4}$

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