Solve $(2 x + 3)^{2} + (2 x - 3)^{2} = (8 x + 6) (x - 1) + 22$

- 1

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Solution

The correct option is A $- 1$
$(2 x + 3)^{2} + (2 x - 3)^{2} = (8 x + 6) (x - 1) + 22$

$\Rightarrow$ $4 x^{2} + 12 x + 9 + 4 x^{2} - 12 x + 9 = 8 x^{2} - 8 x + 6 x - 6 + 22$

$\Rightarrow$ $8 x^{2} + 18 = 8 x^{2} - 2 x + 16$

$\Rightarrow$ $2 x = - 2$

$\Rightarrow$ $x = \frac{- 2}{2}$

$∴$ $x = - 1$

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