Question

Solve $2x+3y=11$ and $2x-4y=-24$ and hence find the value of ${}^{\prime }{m}^{\prime }$ for which $y=mx+3$.

Answer 1

$2x+3y=11$

$2x-4y=-24$

$y=mx+3$

$\frac{2x+3y=112x-4y=-24-++}{7y=35}$

$y=5$

$2x=11-15$

$x=-2$

Put the value of $x$ and $y$

$y=mx+3$

$5=m(-2)+3$

$5-3=-2m$

$2=-2m$

$m=-1$