Question

Solve:
$\frac{2x-(7-5x)}{9x-(3+4x)}=\frac{7}{6}$

Answer 1

$\frac{2x-(7-5x)}{9x-(3+4x)}=\frac{7}{6}$

$\Rightarrow \frac{2x-7+5x}{9x-3-4x}=\frac{7}{6}$

$\Rightarrow \frac{7x-7}{5x-3}=\frac{7}{6}$

$\Rightarrow 6(7x-7)=7(5x-3)$ (by cross multiplication)

$\Rightarrow 42x-42=35x-21$

$\Rightarrow 42x-35x=42-21$

$\Rightarrow 7x=21$

$\Rightarrow x=\frac{21}{7}=3$

$\therefore x=3$