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Byju's Answer
Standard XII
Mathematics
Combination
Solve : 31 ...
Question
Solve :
3
1
×
10
C
1
+
3
2
×
10
C
2
+
3
3
×
10
C
3
+
.
.
.
.
+
3
10
×
10
C
10
=
?
Open in App
Solution
3
1
×
10
C
1
+
3
2
×
10
C
2
+
3
3
×
10
C
3
+
.
.
.
.3
10
×
10
C
10
=
?
(
1
+
x
)
n
=
n
C
0
+
n
C
1
×
a
x
1
+
n
c
2
x
2
+
.
.
.
.
.
.
n
C
n
x
n
Put
x
=
3
and
n
=
10
(
1
+
3
)
10
=
10
C
0
+
10
C
1
×
3
+
10
C
2
×
3
2
+
10
C
10
3
10
3
×
10
C
1
+
3
2
×
10
C
2
+
3
3
×
10
C
3
+
.
.
.
.
.
.
.
.
.
.
.
3
10
×
10
C
10
=
(
4
)
10
−
1
Suggest Corrections
0
Similar questions
Q.
The value of
(
21
C
1
−
10
C
1
)
+
(
21
C
2
−
10
C
2
)
+
(
21
C
3
−
10
C
3
)
+
(
21
C
4
−
10
C
4
)
+
…
.
+
(
21
C
10
−
10
c
10
)
is ?
Q.
The value of
(
21
C
1
−
10
C
1
)
+
(
21
C
2
−
10
C
2
)
+
(
21
C
3
−
10
C
3
)
+
(
21
C
4
−
10
C
4
)
+
⋯
+
(
21
C
10
−
10
C
10
)
is:
Q.
The sum
1
2
10
C
0
−
10
C
1
+
2
⋅
10
C
2
−
2
2
⋅
10
C
3
+...+
2
9
⋅
10
C
10
is equal to
Q.
The value of
(
21
C
1
−
10
C
1
)
+
(
21
C
2
−
10
C
2
)
+
(
21
C
3
−
10
C
3
)
+
(
21
C
4
−
10
C
4
)
+
.
.
.
+
(
21
C
10
−
10
C
10
)
is
Q.
The value of
10
C
1
+
10
C
2
+
10
C
3
+
.
.
.
+
10
C
9
is
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