Solve 320 - 3-4- 36 - 13-2-

(3^2)^0 + 3^ 4× 3^6 + (13)^ 2=1+3^ 4+6+3^2=1+3^2+3^2=1+9+9=19 ...

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Zeroes of a Polynomial

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Question

Solve $(3^{2})^{0} + 3^{- 4} \times 3^{6} + (\frac{1}{3})^{- 2}$ =

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Solution

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