Solve: 3(2x – 3) = 4(2x + 4)
$[2 M a r k s]$

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Solution

3(2x – 3) = 4(2x + 4)

6x – 9 = 8x + 16
$[1 M a r k]$
6x – 8x = 16 + 9

-2x = 25

x = -25/2
$[1 M a r k]$

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Similar questions

Solve the following equations for x:

(i) $2^{2 x} - 2^{x + 3} + 2^{4}$ =0

(ii) $3^{2 x + 4} + 1 = 2 . 3^{x + 2}$

3 (2 x - 1)^{2} + 4 (2 x - 1) - 4 = 0

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\frac{- 4 (2 x - 1)}{3 - x} = \frac{4}{7}

4 (2 x - 3) + 5 (3 x - 4) = 14

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