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Question

Solve: 3(2x+y)=7xy and 3(x+3y)=11xy;

where, x0,y0

A
x=3;y=12
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B
x=1;y=32
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C
x=4;y=2
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D
x=3;y=4
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Solution

The correct option is C x=1;y=32
Dividing both the equations by xy, we get:
3x+6y=7;3y+9x=11
Multiplying the 2nd equation by -2 and Adding
15x=15;y=32andx=1

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