Question

Solve:
$3\left(4+7\right)+\left\{5\times 1\times 4÷2+2\left(4-2\right)\right\}$

Answer 1

$3\underset{–}{(4+7)}+\{5\times 1\times 4÷2+2\underset{–}{(4-2)}\}$

the question is of BODMAS, so we will start by solving the brackets

$=3\left(11\right)+\{5\times 1\times 4÷2+\underset{–}{2\left(2\right)}\}$

$=33+\{5\times 1\times \underset{–}{4÷2}+4\}$

$=33+\{\underset{–}{5\times 1\times 2}+4\}$

$=33+\left\{\underset{–}{10+4}\right\}$

$=33+\left\{14\right\}$

$=33+14$

$=47$