Question

solve:

$\frac{3}{8}+\frac{7}{2}+\left(\frac{-3}{5}\right)+\frac{9}{8}+\left(\frac{-3}{2}\right)+\frac{6}{5}$

Answer 1

$\frac{3}{8}+\frac{7}{2}+(-\frac{3}{5})+\frac{9}{8}+(-\frac{3}{2})+\frac{6}{5}$

$=\frac{3}{8}+\frac{7}{2}+\frac{9}{8}+\frac{6}{5}+(-\frac{3}{5})+(-\frac{3}{2})$

$=\frac{3}{2}+\frac{7}{2}+\frac{6}{5}+(-\frac{3}{5})+(-\frac{3}{2})$

$=\frac{3}{2}+\frac{7}{2}+\frac{6}{5}-\frac{3}{5}-\frac{3}{2}$

$=\frac{7}{2}+\frac{6}{5}-\frac{3}{5}$

$=\frac{7}{2}+\frac{3}{5}$

$=\frac{7\times 5+3\times 2}{10}$

$=\frac{41}{10}$