Solve: $3 {tan}^{2} θ - 1 = 0$

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Solution

$3 {tan}^{2} θ = 1$
$⟹ {tan}^{2} θ = \frac{1}{3} = {tan}^{2} \frac{π}{6}$
$⟹ θ = n π \pm \frac{π}{6}$ $(n \in Z)$

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