Solve: 3x−1×52y−3=225
3x−1×52y−3=2253x−1×52y−3=9×253x−1×52y−3=32×52x−1=2x=32y−3=22y=5y=52
Solve the following equations:
(i)3x+1=27×34(ii)42x=(3√16)−6y=(√8)2(iii)3x−1×52y−3=225(iv)8x+1=16y+2 and (12)3+x=(14)3y(v)4x−1×(0.5)3−2x=(18)x(vi)√ab=(ba)1−2x,where a,b are distinct positive primes.