Solve:
$3 x + 2 y = 13 4 x - y = 10$

Open in App

Solution

$3 x + 2 y = 13 \dots (1) 4 x - y = 10 y = 4 x - 10 3 x + 2 (4 x - 10) = 13 3 x + 8 x - 20 = 13 11 x + 20 = 13 11 x = 33 x = 3 y = 4 (3) - 10 12 - 10 = 2 x = 3; y = 2$

Suggest Corrections

Similar questions

3 x + 2 y + 25 = 0, 2 x + y + 10 = 0

3 x + 2 y \leq 24, x + 2 y \leq 16, x + y \leq 10, x \geq 0, y \geq 0

Z = 3 x + 2 y

x + 2 y \leq 10, 3 x + y \leq 15, x, y \geq 0

\frac{7}{3^{^{x}}} - \frac{6}{2^{y}} = 15

\frac{8}{3^{x}} = \frac{9}{2^{y}}

Z = 3 x + 2 y

x + 2 y \leq 10, 3 x + y \leq 15, x, y \geq 0

Join BYJU'S Learning Program