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Exponents with Like Bases

Solve: 321/...

Question

Solve: $32^{1 / 5}$ .

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Solution

Now,
$32^{1 / 5}$
$= (2^{5})^{1 / 5}$
$= 2$ .

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Similar questions

{⎛ ⎜ ⎝ 32^{\frac{1}{5}} ⎞ ⎟ ⎠}^{- 2} + 4

Q. Solve the following equation:

{log}_{1 / 3} (2 {(\frac{1}{2})}^{x} - 1) = {log}_{1 / 3} ({(\frac{1}{4})}^{x} - 4)

32^{\frac{1}{5}}

32^{1 / 5}

32^{\frac{1}{5}}

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