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Question

Solve -
35x212ax+(a2b2)=0

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Solution

given,

35x212ax+(a2b2)=0

35x212ax+a2b2=0

a=35,b=12a,c=a2b2

x=(12a)±(12a)2435(a2b2)2×35

x=2(6a+a2+b235)70

x=6a±a2+35b235

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