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Roots of Quadratic Equation

Solve : 35y...

Question

Solve : $35 y^{2} + 13 y - 12$

y = \frac{3}{7}

and

y = \frac{- 4}{5}

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y = \frac{1}{7}

and

y = \frac{- 2}{5}

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y = \frac{- 5}{7}

and

y = \frac{2}{5}

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y = \frac{2}{9}

and

y = \frac{- 11}{5}

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Solution

The correct option is A $y = \frac{3}{7}$ and $y = \frac{- 4}{5}$
$35 y^{2} + 13 y - 12 = 0$

$35 y^{2} - 15 y + 28 y - 12 = 0$

$5 y (7 y - 3) + 4 (7 y - 3) = 0$

$(5 y + 4) (7 y - 3) = 0$

$5 y + 4 = 0$ or $7 y - 3 = 0$

$y = - \frac{4}{5}$ or $y = \frac{3}{7}$

Suggest Corrections

Similar questions

F a c t o r i s e : 4 y^{2} - 12 y + 9

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The possible expressions for the adjacent sides of the rectangle having

$35 y^{2} + 13 y - 12$ as its area are ____ and ____

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