Question

Solve:

$37x+41y=70$ and
$41x+37y=86$.

Answer 1

We have,
$37x+41y=70$ (i)
$41x+37y=86$ (ii)

Adding equation (i) and (ii), we get
$78x+78y=156\Rightarrow x+y=2$ (iii)

Substracting equation (ii) from equation (ii), we get
$4x-4y=16\Rightarrow x-y=4$ ..(iv)

Adding equation (iii) and (iv), we get
$2x=6\Rightarrow x=3$

Putting $x=3$ in equation (iii), we get $y=-1$

Hence, $x=3$ and $y=-1$ is the solution of the given system of equations.