Solve:
$3 a^{2} - 4 a b + 6 b^{2} - (3 a^{2} - 8 a b - 2 b^{2})$

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Solution

Consider the given expression.
$3 a^{2} - 4 a b + 6 b^{2} - (3 a^{2} - 8 a b - 2 b^{2})$
$\Rightarrow 3 a^{2} - 4 a b + 6 b^{2} - 3 a^{2} + 8 a b + 2 b^{2}$
$\Rightarrow 4 a b + 8 b^{2}$

Hence, this is the answer.

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Similar questions

(3 a^{2} - 8 a b - 2 b^{2}) - (3 a^{2} - 4 a b + 6 b^{2}) = - 4 a b - 8 b^{2}

3 a^{2} + 8 a b + 2 b^{2}, 3 a^{2} + 4 a b + 6 b^{2}

-

3 a^{2} + 7 a b - 6 b^{2}

State True or False:

On subtracting $a^{2} + a b + b^{2}$ from $4 a^{2} - 3 a b + 2 b^{2}$ , the answer is $3 a^{2} - 4 a b + b^{2}$ .

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