(3a+4b)× (4a+3b) 3a(4a+3b)+4b(4a+3b) ⇒ 12a^2+9ab+16ab+12b^2 ⇒ 12a^2+25ab+12b^2 ⇒ 12[a^2+b^2 2ab]+ab =12[a+b]^2+ab ...

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Simplification of an Expression

Solve 3a+4b ...

Question

Solve
$(3 a + 4 b) \times (4 a + 3 b)$

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Solution

$(3 a + 4 b) \times (4 a + 3 b)$
$3 a (4 a + 3 b) + 4 b (4 a + 3 b)$
$\Rightarrow 12 a^{2} + 9 a b + 16 a b + 12 b^{2}$
$\Rightarrow 12 a^{2} + 25 a b + 12 b^{2}$
$\Rightarrow 12 [a^{2} + b^{2} - 2 a b] + a b$
$= 12 [a + b]^{2} + a b$

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How can I solve the eqn

4a=3b &

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Subtract: (3a - 4b + 5c) from (4a - b + 6c).

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