Solve $3 a + 5 b = 26$ ; $a + 5 b = 22$

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Solution

$3 a + 5 b = 26$ ......................(i)
$a + 5 b = 22$ ........................(ii)

$(i) - (i i) ⟹ 2 a = 4$

$∴ a = 2$

$f r o m (i i) ⟹ 2 + 5 b = 22$

$⟹ 5 b = 20$

$∴ b = 4$

Hence solution is $(a, b) = (2, 4)$

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