We have, 3m #178; + 24m + 36 = 3( m #178; + 8m + 12 ) = 3[ m #178; + 6m + 2m + 12 ] = 3[ m( m + 6 ) + 2( m + 6 ) ] = 3( m + 6 ) ( ...

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Roots of Quadratic Equation

Solve: 3m2+...

Question

Solve: $3 m^{2} + 24 m + 36$

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Solution

We have,
$3 m ² + 24 m + 36$
$= 3 (m ² + 8 m + 12)$
$= 3 [m ² + 6 m + 2 m + 12]$
$= 3 [m (m + 6) + 2 (m + 6)]$
$= 3 (m + 6) (m + 2)$

Hence, this is the answer.

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