Given, 3x^2 4x+203=0 ⇒ 9x^2 12x+20=0 a=9,b= 12,c=20 x= b ±√(b^2 4ac)2a =12 ±√(( 12)^2 4(9)(20))2(9) =23± i43 ...

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Quadratic Formula

Solve : 3x2...

Question

Solve : $3 x^{2} - 4 x + \frac{20}{3} = 0$

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Solution

Given,
$3 x^{2} - 4 x + \frac{20}{3} = 0$
$\Rightarrow 9 x^{2} - 12 x + 20 = 0$
$a = 9, b = - 12, c = 20$
$x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$
$= \frac{12 \pm \sqrt{(- 12)^{2} - 4 (9) (20)}}{2 (9)}$
$= \frac{2}{3} \pm i \frac{4}{3}$

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