Solve $3 x + 2 y + 25 = 0, 2 x + y + 10 = 0$

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Solution

Given equations are,
$3 x + 2 y + 25 = 0$ ................(i)
$2 x + y + 10 = 0$ ...................(ii)

From (ii), we can get
$y = - 2 x - 10$

Substitute $y$ value in equation (i) , we get

$3 x + 2 (- 2 x - 10) + 25 = 0$

$\Rightarrow 3 x - 4 x - 20 + 25 = 0$

$\Rightarrow - x + 5 = 0$

$∴ x = 5$

Hence,
$y = - 2 x - 10 = - 2 (5) - 10 = - 10 - 10 = - 20$

Solution is $(x, y) = (5, - 20)$

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