Solve
3x + 2y = 36
5x + 4y = 64
Given equations:
3x + 2y = 36............(i)
5x + 4y = 64..........(ii)
Multiply (i) by 2 we get
6x + 4y = 72............(iii)
Subtracting (ii) from (iii) we get
x = 8
Substitute x = 8 in (i) we get
3(8) + 2y = 36.
⇒ y = 6